Question

A body moving with uniform acceleration is having velocity 2 m/s & 8m/s at t=1 & t=4 s respectively. Then the average velocity of the particle in the time interval t=1 s to t= 4 s is
(1) 2 m/s
(2)3 m/s
(3)5/3 m/s
(4)5 m/s

Answer 1

Answer:

The average velocity of the particle is 5 m/s.

(4) is correct option.

Explanation:

Given Problem:

A body moving with uniform acceleration is having velocity 2 m/s & 8m/s at t=1 & t=4 s respectively. Then the average velocity of the particle in the time interval t=1 s to t= 4 s is

(1) 2 m/s

(2)3 m/s

(3)5/3 m/s

(4)5 m/s

Solution:

To Find:

Average velocity of the particle.

-------------------

Method:

According to your question,

Initial velocity : $V_i = 2m/s \: at\: t = 1 sec$

Final velocity : $v_2 = 8m/s \:at\:t = 4 sec$

We have to caculate the average velocity of particle  if the acceleration is uniform.

We know that,

Average velocity :

Average velocity is equal to the sum of the initial and final velocity and divided by two.

Now,

$v_a_v_g = \dfrac{v_i+v_f}{2}$

Vaules will be after applying formula,

$v_a_v_g = \dfrac{2+8}{2}$

$v_a_v_g = \dfrac{10}{2} = 5 m/s$

Hence,

The average velocity of the particle is 5 m/s.

Answer 2

Answer:

see photo for your answer