Question

A body moving with uniform acceleration is having
velocity 2 m/s and 8 m/s at t = 1 s and t = 4 s
respectively. Then average velocity of particle in the
time interval t = 1 s to t = 4 s is
(1) 2 m/s
(2) 3 m/s
(3) 5/3 m/s
(4) 5 m/s
​

Answer 1

Answer:

we know that the average of 2 velocities can directly be calculated by given formula :-

Vavg = V1 + V2 / 2

Vavg = 8 + 2 / 2

Vavg = 5 m/s

good day