Physics, asked by varda41, 11 months ago

A body moving with uniform acceleration is having
velocity 2 m/s and 8 m/s at t = 1 s and t = 4S
respectively. Then average velocity of particle in the
time interval t = 1 s to t = 4 s is
(1) 2 m/s
(2) 3 m/s
(3) 5/3 m/s
(4) 5 m/s

Answers

Answered by DevyaniKhushi
5

V_{av} =  \frac{v - u}{t_{f} -t_{i} }  \\  \\  \:  \:  \:  \:  \:  \:  =  \frac{8 - 2}{4 - 1}  =  \frac{6}{3} {ms}^{ - 1}  \:  \:  \:  \:  \:  \:  \: or \:  \: 2 {ms}^{ - 1}


saif2340: wrong answer
DevyaniKhushi: really then u can answer it
Answered by kikibuji
2

Explanation:

plot v- t graph for the given equation

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