Question

A body moving with uniform acceleration is having
velocity 2 m/s and 8 m/s at t = 1 s and t = 4 S
respectively. Then average velocity of particle in the
time interval t = 1 s to t = 4 s is
(1) 2 m/s
(2) 3 m/s
(3) 5/3 m/s
(4) 5 m/s
nary
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Answer 1

Answer:

(4) 5 m/s

Explanation:

if, acceleration is constant,

avg velocity = (initial velocity + final velocity)/2

avg velo = (2+8)/2 = 5 m/s

Answer 2

Answer:

The average velocity of the particle is 5 m/s.

(4) is correct option.

Explanation:

Given that,

Initial velocity $v_{i}=2\ m/s$ at t = 1 sec

Final velocity $v_{2}=8\ m/s$ at t = 4 sec

We need to calculate the average velocity of particle

If the acceleration is uniform.

Average velocity :

Average velocity is equal to the sum of the initial and final velocity and divided by 2.

In mathematically term,

$v_{avg}=\dfrac{v_{i}+v_{f}}{2}$

Put the value into the formula

$v_{avg}=\dfrac{2+8}{2}$

$v_{avg}=5\ m/s$

Hence, The average velocity of the particle is 5 m/s.