Question

A body moving with uniform acceleration moves 27.5 m and 39.5 min the 8th and 12th second of its motion. Find its initial velocity and acceleration

Answer 1

Answer:

s

n

distance travelled in n sec-distance travelled in (n-1) sec

s

n

=(u

1

n+

2

1

an

2

)−(u

1

(n−1)+

2

1

a(n−1)

2

)

=u

1

+

2

1

a(n

2

−(n−1)

2

)

=u

1

+

2

a

(+2n−1)

=u

1

+an−

2

a

Comparing with: s

n

=0.4n+9.8

a=0.4,u

1

−

2

0.4

=9.8

u

1

−

2

0.4

=9.8

u

1

=10 m/s

Explanation:

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