Physics, asked by kajalnth456, 1 month ago

a body moving with uniform acceleration of 2m/s² has covered a distance of 1/5 km in 10 seconds. find its initial and final velocity?​

Answers

Answered by Yuseong
5

Answer:

Initial velocity = 10 m/s

Final velocity = 30 m/s

Explanation:

As per the provided information in the given question, we have :

  • Acceleration (a) = 2m/s²
  • Distance (s) = 1/5 km
  • Time (t) = 10 seconds

We are asked to calculate initial velocity (u) and final velocity (v).

Let us first convert distance into its Standard form.

 \\ \longrightarrow \sf{\quad {s = \dfrac{1}{5} \; km }} \\

  • 1 km = 1000 m

 \\ \longrightarrow \sf{\quad {s =\Bigg ( \dfrac{1}{5} \times 1000 \Bigg ) \; m }} \\

 \\ \longrightarrow \bf{\quad\underline {s = 200 \; m }} \\

Calculating initial velocity :

By using the second equation of motion,

 \\ \longrightarrow \quad \pmb{\boxed{\sf {s = ut + \dfrac{1}{2}at^2 }} }\\

  • s denotes distance
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration

Substitute the values, we have :

 \\ \longrightarrow \sf{\quad {200 = u(10) + \Bigg \lgroup \dfrac{1}{2} \times 2 \times (10)^2 \Bigg \rgroup }} \\

 \\ \longrightarrow \sf{\quad {200 = 10u + \lgroup 1 \times 100 \rgroup }} \\

 \\ \longrightarrow \sf{\quad {200 = 10u + 100 }} \\

 \\ \longrightarrow \sf{\quad {200 -100= 10u }} \\

 \\ \longrightarrow \sf{\quad {100= 10u }} \\

 \\ \longrightarrow \sf{\quad {\cancel{\dfrac{100}{10}}= u }} \\

 \\ \longrightarrow \sf{\quad { 10 = u}} \\

 \\ \longrightarrow \bf{\quad\underline { Initial\; velocity= 10 \; m/s}} \\

Therefore, initial velocity of the body is 10 m/s.

Calculating final velocity (v) :

By using the first equation of motion,

 \\ \longrightarrow \quad \pmb{\boxed{\sf {v = u + at}} }\\

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • t denotes time

We found the value of initial velocity above. Substituting all the values we have,

 \\ \longrightarrow \sf{\quad { v = 10 + 2(10)}} \\

 \\ \longrightarrow \sf{\quad { v = 10 + 20}} \\

 \\ \longrightarrow \sf{\quad { v = 30}} \\

 \\ \longrightarrow \bf{\quad\underline { Final \; velocity= 30 \; m/s}} \\

Therefore, final velocity of the body is 30 m/s.

More Information :

Equations of motion :

\boxed{ \begin{array}{cc}    \pmb{\sf{ \quad \: v = u + at \quad}}  \\  \\  \pmb{\sf{ \quad \:  s= ut +  \cfrac{1}{2}a{t}^{2}  \quad \: } } \\ \\  \pmb{\sf{ \quad \:  {v}^{2} -  {u}^{2}  = 2as \quad \:}}\end{array}}

  • v denotes final velocity
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration
  • s denotes distance
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