A body moving with uniform acceleration travels 24m in 6th sec and 44m in 11th sec.find acceleration and initial velocity
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we know that S nth=u+a/2×(2n-1)
then
24=u+a/2×(2×6-1)
48=2u+11a•••••••••(i)
Similarly
44=u+a/2×(2×11-1)
88=2u+21a••••••••(ii)
on solving (i) and (ii)
a=4
putting the value of 'a' in any of the 2 eqns...
88=2u+84
or u=2
therefore initial velocity u, is 2m/s
and acceleration a,is 4m/s^2
then
24=u+a/2×(2×6-1)
48=2u+11a•••••••••(i)
Similarly
44=u+a/2×(2×11-1)
88=2u+21a••••••••(ii)
on solving (i) and (ii)
a=4
putting the value of 'a' in any of the 2 eqns...
88=2u+84
or u=2
therefore initial velocity u, is 2m/s
and acceleration a,is 4m/s^2
Yashanshi1:
it is not an understandable solution
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