Question

a body moving with uniform acceleration travels 50 meter in 5 sec and if 8t covers 14 meter during the 5th second.find out thr initial velocity and acceleration

Answer 1

We have acceleration constant and
S = 50m
t = 5s
St = 14m ( St is distance travel in th second)
St = u+1/2a(2t-1).........(i)
From one we will get u=(28-9a)/2.......(ii)
S=ut+1/2atxt.....(iii)
On putting (ii) in (iii) along with value of t and S we get
$a = 2m \div {s}^{2}$
on putting a in
$u = (28 - 9a)\div 2$

we get u= 5 m/s