Question

A body moving with uniform acceleration Travels 84 metre in the first 6 second and 180 m in the next 5 seconds. find: (a) the initial velocity ,and (b) the acceleration of the body.

Answer 1

initial velocity = 84/6 = 14 m/s
final velocity = 180/5 = 36 m/s
acceleration = (36-14)/11 = 22/11 = 2m/s^2

Answer 2

Answer: The initial velocity is 14 m/s and the acceleration is $a = 2 m/s^2$.

Explanation:

Given that,

Time $t_{1} = 6 s$

$t_{2}=5 s$

Distance $d_{1}=84\ m$

$d_{2}= 180\ m$

The initial velocity is

$v_{1} =\dfrac{84}{6}$

$v_{1}= 14\ m/s$

The final velocity is

$v_{2}=\dfrac{180}{5}$

$v_{2} = 36\ m/s$

The acceleration of the body is

$a = \dfrac{v_{2}-v_{1}}{t_{1}+t_{2}}$

$a = \dfrac{36-14}{11}$

$a = 2 m/s^2$

Hence, The initial velocity is 14 m/s and the acceleration is $a = 2 m/s^2$.