A body moving with uniform acceleration travels distances of 24m amd 64 m during thw first two consecutive intervals of time,each of duration 4s. Determine the initial velocity and acceleration of body
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Answer:
1m/s( inital velocity)
Explanation:
w.k.t,
S1 = ut + 1/2 at square
a =(S - ut) × 2/at square
then,
a = (24 - 4u) × 2/4 square
a = (24 -4u) × 1/8
a = 4(6 - u) /8
= 6 - u /2
S2 =( 8u +1/2 × a64) - ( 4u +1/2 × 1/2 × a16)
after we get
a = 16 - u /6
In both cases,
a are equal , so initial velocity = 1m/s square
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