Question

A body moving with uniform velocity 5u is subject to uniform retardation a. It returns to the
starting point after
(W) Su/a sec
(6) 10u/a sec
(20u/a sec
(d) 10a/u sec​

Answer 1

Step-by-step explanation:

I. By III equation of motion,

v

2

=u

2

+2as

(5v)

2

=u

2

+2as

25v

2

−u

2

=2as

24u

2

=s

2a

∴ Distance travelled =S=

a

12u

2

II. v

2

=u

2

+2as

v

2

=(5u)

2

+2(−a)(

a

12v

2

)

v

2

=25v

2

−24u

2

v

2

=u

2

v=1u

⇒v=−u.

please mark me brainliest