a body moving with velocity 40 metre per second is brought to rest in 20 seconds find out the retardation find also the distance travelled in that time
Answers
Given :
- Initial velocity, u = 40 m/s
- Final velocity, v = 0 m/s (as it brought to rest)
- Time, t = 20 seconds
To find :
- Retardation, a
- Distance travelled, s
According to the question,
➞ v = u + at
Where,
- v = Final velocity
- u = Initial velocity
- a = Acceleration
- t = Time
➞ 0 = 40 + a × 20
➞ 0 - 40 = 20a
➞ - 40 = 20a
➞ - 40 ÷ 20 = a
➞ - 2 = a
So,the retardation is - 2 m/s².
Now,
➞ v² = u² + 2as
Where,
- a = Acceleration
- s = Distance
- u = Initial velocity
- v = Final velocity
➞ (0)² = (40)² + 2 × (-2) × s
➞ 0 = 1600 + (-4s)
➞ 0 - 1600 = - 4s
➞ - 1600 = - 4s
➞ 1600 ÷ 4 = s
➞ 400 = s
So,the distance travelled is 400 meter.
Answer:
Given :-
- A body moving with velocity 40 m/s is brought to rest in 20 seconds.
To Find :-
- What is the retardation and the distance travelled by a body.
Formula Used :-
❶To find acceleration we know that,
❷ To find distance travelled we know that,
where,
- v = Final velocity
- u = Initial velocity
- a = Acceleration
- t = Time
- s = Distance travelled
Solution :-
❶ To find retardation,
Given :
- Final velocity = 0 m/s
- Initial velocity = 40 m/s
- Time = 20 seconds
According to the question by using the formula we get,
⇒ 0 = 40 + a(20)
⇒ 0 - 40 = 20a
⇒ - 40 = 20a
⇒ = a
⇒ - 2 = a
➠ a = - 2 m/s²
The retardation of a body is - 2 m/s² .
❷ To find distance travelled,
Given :
- Final velocity = 0 m/s
- Initial velocity = 40 m/s
- Time = 20 seconds
- Acceleration = - 2 m/s²
According to the question by using the formula we get,
↦ (0)² = (40)² + 2(- 2) × s
↦ 0 = 1600 - 4 × s
↦ 0 = 1600 - 4s
↦ 0 - 1600 = - 4s
↦ - 1600 = - 4s
↦ = s
↦ 400 = s
➥ s = 400 m
The distance travelled by a body is 400 m .