Question

A body of 0.5 kg thrown upwards reaches a maximum height of 5 m. Calculate the work done in throwing the body upwards. solve it

Answer 1

Answer :

Mass of body = 0.5kg

It is thrown vertically upward.

Max. height attained by body = 5m

We have to find work done in throwing the body upwards$.$ :D

◈ WET :-

As per work-energy theorem, Work done in moving object is equal to the change in potential energy.

Potential energy of body of mass m at height H is given by

• U = mgH

Potential energy is measured with respect to reference point.

Therefore, PE at ground = zero

Mathimatical form of WET is given by

• W = ΔPE = Uf - Ui

➝ W = mgH - 0

➝ W = 0.5 × 10 ×5

➝ W = 25J

☃ God Bless :D

Answer 2

Given ,

Mass (m) = 0.5 kg

Height (h) = 5 m

We know that ,

Work = Energy

Potential energy = mgh

Where , g = acceleration due to gravity

Thus ,

Potential energy = 0.5 × 10 × 5

Potential energy = 5 × 5

Potential energy = 25 J

$\therefore$ The work done in throwing the body upward is 25 J