Question

A body of 1 kg initially at rest is moved by force of 0.5N on a
smooth friction-less table. Calculate the work done by force in 10
seconds.​

Answer 1

Answer:

Given,

Mass (m) = 1 kg

Initial Velocity (u) = 0 m/s

Force (F) = 0.5 N

Time (t) = 10 s

Acceleration (a) = F = ma

= 0.5 = 1a

= 0.5 m/s² = a

S = ut+0.5at²

= (0*10) + (0.5*0.5*10*10)

= 25 m

Work Done = Force*Displacement

= 0.5*25 J

= 12.5 J

I hope this helps.

Answer 2

Mass of the body=1kg

Force applied=0.5N

We know F=ma

We can calculate acceleration now

a=F/m

a=0.5m/s^2

Apply

$S=ut+\frac{at^2}{2} \\\\\mapsto S=\frac{0.5 \times 100} {2} \\\\ \mapsto\frac{50}{2} = 25m$

Now, work done= Force x Displacement

=> 0.5 x 25 = 12.5 Joules