A body of 1 kilograms is how to fall freely from a height of 25 m calculate its kinetic energy potential energy and Total energy at the instance it is at a height of 4 m from the Earth when g
equal to 10 M per second square
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Given,
u=40 m/s
For maximum height,v=0 m/s
Using relation,
v2−u2=2gh0−402=2×(−10)×hh=80 cm1−Kinetic energy is equal to potential energy at h'=h/2=80/2=40 cm2−Potential energy of body of mass 10kg is given byP.E=mgh=10×10×80=8000 J
u=40 m/s
For maximum height,v=0 m/s
Using relation,
v2−u2=2gh0−402=2×(−10)×hh=80 cm1−Kinetic energy is equal to potential energy at h'=h/2=80/2=40 cm2−Potential energy of body of mass 10kg is given byP.E=mgh=10×10×80=8000 J
richapandey71217:
Ans. =210J,40J,250J
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3
The velocity of that instant moment
V^2=2as
...... =2.10.(25-4)
..... =420
V=√420
The kinetic energy
Ev=1/2mv^2=1/2*420=210j
The total potential energy is
Ep= m.h.g=1.10.4=40j
Total energy is=210+40=250j
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