Question

A body of 10 kg tied at one end of a 0.3 m wire is
rotated in a horizontal circle. The area of cross-section
of the wire is 10^-6 m^2
and the breaking-stress is
4.8 x 107 N /m2. By how much maximum angular
speed can the body be rotated?​

Answer 1

stress=  

Area

force

​  

 

Force=stress×Area

=4.8×10  

7

×10  

−

6

=48

Now, Force=Tension in wire=mω  

2

r

So, 48=mω  

2

r

⇒  

0.3

48

​  

×  

10

1

​  

=ω  

2

 

⇒ω=4rad/s

Answer 2

Answer:

The answer is as given:

4 rad/s.