Question

a body of 100gm is suspended from a light spring which stretches by 10cm, the force constant of spring will be

A 98x10²dyne/cm
B 9.8x 10²dyne/cm
C 98x10² N/m
D 98x10-² dyne/cm​

Answer 1

Explanation:

A 1m/sB

0.866m/s

C

0.225m/s

D

1.5m/s

Answer

B

Solution

Ei=Ef

0=12×10×(0.15)2−0.1×10×0.15

+12×0.1×v2

∴v=0.866m/s.