Question

A body of 2 g is released from top of smooth inclined plane having inclination angle 30.it takes 3 sec to reach ground if angle got the double what will be time taken​

Answer 1

Answer :

Body takes 3s to reach bottom when angle of inclination is 30°.

We have to find time taken by body to reach bottom when angle of inclination is 60°$.$

★ First of all we need to find distance covered by body in each case. Body will cover equal distance in both cases.

Moreover acceleration of body in both cases will be (g sinθ).

First Case :

➝ d = 1/2 a₁t₁²

➝ d = 1/2 (gsin30°)(3)²

➝ d = 1/2 (10 × 1/2)(9)

➝ d = 45/2

➝ d = 22.5 m

Second case :

➝ d = 1/2 a₂t₂²

➝ 22.5 = 1/2 (gsin60°)(t)²

➝ 45 = (10 × √3/2)(t²)

➝ 45 = 5√3 t²

➝ t² = 9/√3

➝ t² = 3√3

➝ t ≈ 2.3 s