Physics, asked by riteshkrrai2019, 11 months ago

a body of 2 kg fall from rest what will be its kinetic energy during the fall at the end of2 second ​

Answers

Answered by warriorbey2004
0

Answer:

The answer is 400J

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Answered by TwihardsUp
0

Answer:

400 J

Explanation:

KE = 1/2mv*v

h = height

u = initial velocity

g = acceleration due to gravity

t = time taken

By 2nd law of motion,

h = ut + 1/2gt*t

h = (0*2) + 1/2*10*2*2

h = 20  m

By 3rd equation of motion,

v² = u² + 2gh

⇒ v² = 0² + 2*10*20

⇒ v² = 400

⇒ v = 20

KE = 1/2 × 2× 20²

     = 400 J

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