a body of 2 kg falls from rest . what will be its kinetic energy during the fall at the end of 2s
Answers
Answered by
1
Answer:
400j
Explanation:
v = 2g = 20m/s
energy = mv²/2 = v² = 400j
Answered by
0
V=20m/s
Ke=mv*v/2
Ke=400joules
Ke=mv*v/2
Ke=400joules
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