Question

a body of 2 kg Falls from rest what will be its kinetic energy during the fall at the end of 2 seconds ​

Answer 1

Answer:

Pic is below..

Explanation:

Answer 2

Answer:

KE=1/2mv*2

Here, m=2,v=?

v=u+at

=0+at

a=g(falling down so gravitational force acts)

So a=10

v=10*2

=20

KE=1/2*2*(20)*2

=400