Question

A body of 2 kg falls from rest. what will be its kinetic energy during the fall at the end of 2s assume g 10

Answer 1

mass 2 kg
initial velocity 0
time taken 2s
g 10 m/s^2
v=?
using first equation of motion
v=u+ at
v=0+10×2
v=20m/s
k.e=1/2 mv^2
= 1/2×2×20×20
= 400 Joule

Answer 2

ANSWER
.......


➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️

MASS = 2 KG
VELOCITY = 0
TIME = 2 SECOND
G = 10 M / S ^2
V = U + AT
V = 0 + 10 *2
V = 20 M / S
...
K. E = 1 / 2 MV ^2
1 / 2 * 20*20
= 400 JOULE
....


ANSWER IS 400 JOULE

➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️