a body of 2 kg Falls from rest what will be its kinetic energy during the fall at the end of 2 seconds assume g is equals to 10 metre per second square
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M=2Kg
V=10m/s^2
T=2 sec
So,
KE=1/2mv^2
=100
V=10m/s^2
T=2 sec
So,
KE=1/2mv^2
=100
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