Question

A body of 2 kg falls from rest what will be its kinetic energy during fall at the end of 2 seconds is equal to 10 m per second square

Answer 1

v = u+at

v = 0+10*2

v=20m/s

kinetic energy = 1/2mv^2

k.e.= 1/2*2*400

k.e. = 400 Joule

I hope it will help u