Physics, asked by rahul3196, 1 year ago

A body of 2 kg mass makes an elastic collision with another body at rest. The velocity of the 2 kg mass is reduced to one-fourth of the original velocity. However, direction remains unchanged. What is the mass of the body struck?

Answers

Answered by nehar1306
4

Using formula for elastic collision when the target (i.e. second body here) is at rest before collision.  

v1 = (m1 - m2)/(m1 + m2) * u1  

It is given v1 = u1/4 and substituting the value m1 = 2.0 kg,  

u1/4 = (2 - m2)/(2 + m2) * u1  

Divide by u1  

1/4 = (2 - m2)/(2 + m2)  

Or 2 + m2 = 4 * (2 - m2)  

Or 2 + m2 = 8 - 4m2  

Or m2 + 4m2 = 8 - 2  

Or 5m2 = 6  

Or m2 = 6/5 = 1.2 kg  

Ans: 1.2 kg

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