Question

A body of 200 N weight is pulled by a force of 500 N on an inclined plane of θ=30° slope as shown in Figure. If the body travels the distance of 10 m during 60 seconds, what will be the work done on the body and what will be the amount of power consumed?

Answer 1

Explanation:

w= fscos theta

w= 500×10× cos30

w= 500×10×√3/2

w=2500√3

p=w/t

p=(2500√3)/60

p=(250√3)/6

Answer 2

Answer:

Explanation:

w= fscos theta

w= 500×10× cos30

w= 500×10×√3/2

w=2500√3

p=w/t

p=(2500√3)/60

p=(250√3)/6

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