A body of 200 N weight is pulled by a force of 500 N on an inclined plane of θ=30° slope as shown in Figure. If the body travels the distance of 10 m during 60 seconds, what will be the work done on the body and what will be the amount of power consumed? with detailed steps
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Answer:
Explanation:
w= fscos theta
w= 500×10× cos30
w= 500×10×√3/2
w=2500√3
p=w/t
p=(2500√3)/60
p=(250√3)/6
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