Math, asked by pallavinitin29, 11 days ago

a body of 20kg mass is moving with 30m/s. its velocity increases to 60m/s in 10s. find its acceleration, change in momentum of body and external force required for this change​

Answers

Answered by vedagoutam
0

Answer:

ANSWER

Step-by-step explanation:

3 M/S² IS ACCELERATION

-600 kg m/s

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Answered by ItzMeSam35
3

Given ,

Mass \: m = 20 kg

Initial  \: Velocity \:  u = 30 \: m ^{ - 1}

Final  \: Velocity  \: v = \: 60 \: m \: s^{ - 1}

Time \: t \:  = 10s

Acceleration \:  a  =  ( \frac{v - u}{t} )

 = ( \frac{60 \: m \: s ^{ - 1} - \:  30  \: m \: s ^{ - 1} }  {10 \: s} )

 =  \frac{30 \: m \: s^{ - 1} }{10 \: s}

 = 3 \: m \: s ^{ - 2}

Change \:  In \:  Momentum \:  =  \: ∆p \:  = m∆v

 = m \:  \times (v - u)

 = 20 \: kg \:  \times (60 - 30 \: m \: s^{ - 1} )

 = 20  \:  \times  \: 30 \: m \: s ^{ - 1}

 =  \: 600 \: kg \: ms ^{ - 1}

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