Question

A body of 2kg fall from rest .what will be it's kinetic energy during the fall at the end of 2sec

Answer 1

Explanation:

after two sec (g=10)

v=u+gt

initial velocity is zero

so,v=0+10(2)

v=20

KE=1/2mvsquare

KE=0.5*20*20

Therefore KE is 400Joules