Question

a body of 2kg falls from rest.What will be its kinetic energy during the fall at the end of 2s?(assume g=10m/s)

​

Answer 1

Answer:

400

Explanation:

v=u+at

u=0 (falling from rest)

a=10 m/s^2

t=2 s

So v=20 m/s

K.E=1/2mv^2

K.E=1/2×2×20×20

K.E=400