Question

A body of 2kg is moving along positive x-direction with a velocity of 5 meter per second . Now a force of 10 of root 2 N is applied at an angle 45 degree with x- axis . its velocity after 3 sec is

Answer 1

Explanation:

Initial velocity along X axis, Ux = 5 m/s

Acceleration upon the action of force = F cos θ / mass

= 10 √2 x (1/√2) / 2

= 10/2

= 5 m/s2.

Now, Vx = Ux + axt

Vx = 5 + [5 x 3]

Vx = 20m/s

Now, displacement alonf Y axis also needs to be considered as the force will displace the body from its straight line path.

So, Vy = Uy + ayt

Vy = 0 + 5 x 3 = 15 m/s

Now, resultant V = √(Vx2 + Vy2)

= √(202 + 152)

Thus,velocity after 3 sec = 25 m/s.

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Answer 2

Answer:

same as above..........