A body of 2kg is moving along positive x-direction with a velocity of 5 meter per second . Now a force of 10 of root 2 N is applied at an angle 45 degree with x- axis . its velocity after 3 sec is
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Explanation:
Initial velocity along X axis, Ux = 5 m/s
Acceleration upon the action of force = F cos θ / mass
= 10 √2 x (1/√2) / 2
= 10/2
= 5 m/s2.
Now, Vx = Ux + axt
Vx = 5 + [5 x 3]
Vx = 20m/s
Now, displacement alonf Y axis also needs to be considered as the force will displace the body from its straight line path.
So, Vy = Uy + ayt
Vy = 0 + 5 x 3 = 15 m/s
Now, resultant V = √(Vx2 + Vy2)
= √(202 + 152)
Thus,velocity after 3 sec = 25 m/s.
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Answer:
same as above..........
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