Question

A body of 5 kg initial at rest is subjected to a force of 20 newton . Calculate the kinetic energy accuried by the body in 10 sec

Answer 1

from second law of motion, F=ma
F=5×v-0/10
20×10/5=v
v=40m/s
kinetic energy= 1/2×5×(40)^2
=1/2×5×1600
=5×800
=4000J