a body of 5 kg initially at rest is subjected to a force of 20 Newton what is the kinetic energy acquired by the body at the end of 10 seconds
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Hey!
Given,
Mass (m) = 5kg
Force(f) = 20 N
Time(t) = 10 sec
Then, Acceleration(a) = f/m = 20/5 = 4 m/s²
Now,
We know,
v = u + at
v = 0 + 4*10
v = 40 m/s
Now,
K.E = 1/2mv²
K.E = 1/2*5*(40)²
K.E = 4000 J
Given,
Mass (m) = 5kg
Force(f) = 20 N
Time(t) = 10 sec
Then, Acceleration(a) = f/m = 20/5 = 4 m/s²
Now,
We know,
v = u + at
v = 0 + 4*10
v = 40 m/s
Now,
K.E = 1/2mv²
K.E = 1/2*5*(40)²
K.E = 4000 J
duragpalsingh:
Hope It's correct
yeah it's correct
Thanks!
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