a body of 5 kg initially at rest is subtended to a force of 20 Newton what is the kinetic energy acquired by the body at the end of 10 second
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Answered by
1
F=ma
20 = 5 × x
4 = x
Then
U , initial velocity =0
V , final velocity = y
T. Time = 10
v = u +at
= 0+ (4×10 )
V = 40
Then kinetic energy = 1/2 m × (velocity )sq
= 1/2 × 5 × 1600
= 4000 J
Hope this helps
20 = 5 × x
4 = x
Then
U , initial velocity =0
V , final velocity = y
T. Time = 10
v = u +at
= 0+ (4×10 )
V = 40
Then kinetic energy = 1/2 m × (velocity )sq
= 1/2 × 5 × 1600
= 4000 J
Hope this helps
Answered by
0
since m=5kg and F=20N
therefore first find a which is F=ma here a =4m/s2
now, using v=u +at
find v as u=0, t=10s and a =4
therefore v =40 m/s
finally KE=1/2mv2
so putting all values we get KE=4000J
therefore first find a which is F=ma here a =4m/s2
now, using v=u +at
find v as u=0, t=10s and a =4
therefore v =40 m/s
finally KE=1/2mv2
so putting all values we get KE=4000J
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