Question

A body of 5 kg mass placed on a smooth horizontal surface experiences a force varying with displacement of body as shown in figure. The Kinetic energy of body when force ceases to act on it is
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Answer 1

Answer:

250 Joule

Explanation:

This could be done only by using kinetic energy=Area under graph

1/2m$v^{2}$=Work done

1/2*5*v^{2}=1/2*20*10+1/2*(10+20)*5+1/2(10+5)*10

=100+75+75

=250 Joule