Physics, asked by Pranitha6616, 10 months ago

A body of 50 kg is in a lift moving down with an accleration 9.8ms^-2. The apparent weight of the body is

Answers

Answered by ParamPatel
0

HEYA GM ❤

★ WHEN LIFT MOVING DOWNWARDS.....

APPARENT WEIGHT / F = m(g-a)

F = 50 ( 9.8 + 9.8 ) = 50(19.6)

Apparent Weight = 980 N

TQ ❤ ❤

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