a body of 5kg starts from rest and travels with uniform accleration 2m/sec^2 for 10 sec find the final velocity attained by the body and work done by he force
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Answer:
- final velocity attained by the body
- s=ut+1/2at^2
- s=0+1/2×2×100
- s=100m
- f =ma
- f = 5kg ×2m/s
- f = 10 N
- work done =f×s
- work done =10×100
- work done =1000J
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