Question

A body of 5kg weight kept on a rough inclined plane of angle 30∘ starts sliding with a constant velocity.Then the coefficient of friction is (assume g=10m/s2)

Answer 1

for constant velocity, acceleration is zero. So in the sliding direction the force will be mgsin30 and in opposite it will be , umgcos30 so
umgcos30= mgsin30
u*root 3/2 = 1/2
so u =1 / root 3 answer.