A body of 90 kg f on the surface of earth. How much will it weigh on the surface of moon whose mass is 1/9 and radius is ½ of that of earth?
Answers
Answered by
7
Hello
weight of body on earth = 90 kg
we know weight is force
then,
F = ma
90 = m x a ( here a = g )
where g = acceleration due to gravity on earth
90 = m x g
g = 9.8 m/s² for earth
90 = m x 9.8
m = 90 / 9.8 = 9.18 kg
as mass is constant
weight of body on moon = mass of body x gravitational force of moon
The gravitational force of moon is 1/6 th of earth
weight of body on moon = 9.18 x 9.8/6 = 14.994 kg
weight of body on earth = 90 kg
we know weight is force
then,
F = ma
90 = m x a ( here a = g )
where g = acceleration due to gravity on earth
90 = m x g
g = 9.8 m/s² for earth
90 = m x 9.8
m = 90 / 9.8 = 9.18 kg
as mass is constant
weight of body on moon = mass of body x gravitational force of moon
The gravitational force of moon is 1/6 th of earth
weight of body on moon = 9.18 x 9.8/6 = 14.994 kg
Answered by
1
Answer:
Hello
weight of body on earth = 90 kg
we know weight is force
then,
F = ma
90 = m x a ( here a = g )
where g = acceleration due to gravity on earth
90 = m x g
g = 9.8 m/s² for earth
90 = m x 9.8
m = 90 / 9.8 = 9.18 kg
as mass is constant
weight of body on moon = mass of body x gravitational force of moon
The gravitational force of moon is 1/6 th of earth
weight of body on moon = 9.18 x 9.8/6 = 14.994 kg
Explanation:
Similar questions