Question

A body of 90 kg f on the surface of earth. How much will it weigh on the surface of moon whose mass is 1/9 and radius is ½ of that of earth?

Answer 1

Hello 

weight of body on earth = 90 kg 

we know weight is force 

then, 

F = ma 

90 = m x a ( here a = g ) 

where g = acceleration due to gravity on earth 

90 = m x g 

g = 9.8 m/s² for earth 

90 = m x 9.8 

m = 90 / 9.8 = 9.18 kg 

as mass is constant 

weight of body on moon = mass of body x gravitational force of moon 

The gravitational force of moon is 1/6 th of earth 

weight of body on moon = 9.18 x 9.8/6 = 14.994 kg 

Answer 2

Answer:

Hello  

weight of body on earth = 90 kg  

we know weight is force  

then,  

F = ma  

90 = m x a ( here a = g )  

where g = acceleration due to gravity on earth  

90 = m x g  

g = 9.8 m/s² for earth  

90 = m x 9.8  

m = 90 / 9.8 = 9.18 kg  

as mass is constant  

weight of body on moon = mass of body x gravitational force of moon  

The gravitational force of moon is 1/6 th of earth  

weight of body on moon = 9.18 x 9.8/6 = 14.994 kg

Explanation: