Question

A body of a mass 2kg is moving on a smooth horizontal platform with an initial velocity of 3m/s.The force of gravity acting on the body is 20.The distance covered by the body in 2s is:

Answer 1

Explanation:

From above figure

A→B

u = 4m/s v=0 t=2sec a=?

v=u+at

0=4+a(2)

a=−2m/s

2

so,

force = ma

=2×2=4N

Answer 2

Answer:

◍Given:

• A body of a mass 2kg is moving on a smooth horizontal platform with an initial velocity of 3m/s.The force of gravity acting on the body is 20

◍To Find:

• The distance covered by the body in 2s is:

◍Solution:

$From \: above \: figure \\ </p><p></p><p>A→B \\ u = 4 \frac{m}{s} \: \: v = 0 \: \: \: t = 2 \sec \: \: \: \: a = ?</p><p> \\ v = u + at \\ 0 = 4 + a(2) \\ a = - 2 \frac{m}{ {s}^{2} } \\ so \: force \: = ma \\ = > 2 \times 2 = 4n</p><p></p><p>$