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a body of a mass 2kg moving on a smooth track has kinetic energy of 100 j.after traveling a distance 1 m, 19% of initial energy is lost due to air friction .the final speed of body will be​

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Answered by Aaryanpatel5
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Explanation:

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Answered by Anonymous
2

\LARGE\mathfrak{\underline{\underline{\red{Question: }}}}

A body of a mass 2kg moving on a smooth track has kinetic energy of 100 j.after traveling a distance 1 m, 19% of initial energy is lost due to air friction .the final speed of body will be?

\LARGE\mathfrak{\underline{\underline{\pink{Solution: }}}}

 :  \implies  \sf{k_j =  \frac{1}{2} mv^{2} = 80 J}  \\ :  \implies  \sf{ \frac{80}{100}  \times ki = 80J} \\  :  \implies \sf{ki =   :  \cancel\frac{{ 80} \times 100}{80} } \\   :  \implies \sf{ \frac{1}{2}  {mv}^{2}  = 100 J} \\  \\  \mathfrak \purple{let \: the \: initial \: velocity \: energy \: be  \: \sf{ki.}} \\  :  \implies\sf{ki = 100J} \\ :  \implies \sf{ \frac{1}{{ \not 2}} \times { \not 2  }} \times  {v}^{2}  = 100 \\ :  \implies \sf{ {v}^{2} =100  } \\  \\ \mathfrak \purple{ \therefore initial \: velocity \: has \: 10m/s}

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