a body of a mass 500g is moving with a speed 20m/s when brakes are applied it comes to rest in next 0.05s calculate the change in momentum and the average force applied
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A force of 500 N acts on a body of mass 1000 kg and the body is brought to rest within a distance of 64 m. Find the initial velocity and the time taken by the body before to come to rest.
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Answer
Correct option is
A
8 ms
−1
,16s
Solution: Force, F= 500 N ; mass of the body, m= 1000 kg.
From newtons second law of motion,
F = ma, where F, m and a are the force , mass and acceleration respectively.
a=
m
F
=
1000
500
=0.5ms
−2
To find initial velocity , consider the equation of motion v
2
=u
2
+2 as
Since the body is retarding a=−0×5ms
−2
and since it comes to rest v =0
∴0=u
2
+(2×(−0×5)×64)
0=u
2
−(1×64)⇒u
2
=64
⇒u=
64
=8ms
−1
Tofindthetimetaken,considertheequationofmotionv=u+at
0=8−0×5×t⇒t=
0.5
8
=16s
∴u= 8 ms
−1
, t=16sanda=−0×5ms
−2
Answer:
In chemistry, an element is a pure substance consisting only of atoms that all have the same number of protons in their atomic nuclei. Unlike chemical compounds, chemical elements cannot be broken down into simpler substance by chemical means.
Answer:
In chemistry, an element is a pure substance consisting only of atoms that all have the same number of protons in their atomic nuclei. Unlike chemical compounds, chemical elements cannot be broken down into simpler substance by chemical means.