A body of a mass 50kg is being lifted by a lift in an office. The force exerted by the body on the lift floor when it is moving with a uniform acceleration of 1.2 m/s2 is..
Answers
Given:-
- Mass of body (m) = 50kg
- Acceleration (a) = 1.2m/s².
To Find:-
- Force exerted by the body .
Solution:-
As we know that
⟹ Force = Mass×Acceleration
Put the value which is given above
⟹ F =m×a
⟹ F = 50×1.2
⟹ F = 60N.
∴ The force exerted by the body on the lift floor is 60N.
Additional Information!!
The rate of change of velocity at per unit time is called acceleration .
✧ SI unit of acceleration is m/s²
✧ It is vector Quantity ( both magnitude and direction)
✧ Product of mass and acceleration is called force.
✧ SI unit of Force is Newton.
✧ It is denoted by N.
✧ Force is vector Quantity i.e., both Magnitude and direction.
✧ Mathematical term
⟹ Force = Mass×Acceleration
Given:-
Mass of body (m) = 50kg
Acceleration (a) = 1.2m/s².
To Find:-
Force exerted by the body .
Solution:-
As we know that
⟹ Force = Mass×Acceleration
Put the value which is given above
⟹ F =m×a
⟹ F = 50×1.2
⟹ F = 60N.
∴ The force exerted by the body on the lift floor is 60N.
Additional Information!!
The rate of change of velocity at per unit time is called acceleration .
✧ SI unit of acceleration is m/s²
✧ It is vector Quantity ( both magnitude and direction)
✧ Product of mass and acceleration is called force.
✧ SI unit of Force is Newton.
✧ It is denoted by N.
✧ Force is vector Quantity i.e., both Magnitude and direction.
✧ Mathematical term
⟹ Force = Mass×Acceleration