Question

A body of density 5 gram per centimetre cube weighs 0.5 kgf in air it is immersed in water of density 1 gram per centimetre cube calculate the apparent weight of the solid in water

Answer 1

Answer:

Density ρ = 5000 kg/m

3

Weight = 0.5 kg f in air

mass M = 0.5 kg

Volume V = M / ρ

= 0.5 / 5000 = 10

−4

m

3

mass of water displaced = V

∗

density of water

= 10

−4

∗1000 = 0.1 kg

Apparent weight = wt in air - wt of water displaced

= 0.5 kg f - 0.1 kg f

= 0.4 kg f

Answered By

Answer 2

Explanation:

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