a body of density 800kg/M3 is put into the water. find the part of the body float above the surface of the water
Answers
Answered by
1
Answer:
AS we know
fraction of body immersed =
ρ
(
liquid)
ρ
(
solid)
=
1000
800
= 0.8 ( as density of water = 1000 kg m
−3
)
so percentage volume of solid cylinder inside the water = 0.8×100 = 80%
so % volume of cylinder outside the water = 100 - 80 =20
hence option (D) is correct
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