A body of density d1 is balanced by a body of weight mg and density d2
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The bodies with two different densities like d1 and d2, and they are combined.
When they are combined, the densities integrate as a whole of one body with one particular density.
To calculate that new density, we use the product of the densities of the two bodies.
Thus, d3, the density of the combined bodies is equals d1 × d2.
When they are combined, the densities integrate as a whole of one body with one particular density.
To calculate that new density, we use the product of the densities of the two bodies.
Thus, d3, the density of the combined bodies is equals d1 × d2.
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Answer:
m1=m2[1-d1/d2]/[1-d1/d2]
Explanation:
let
the first body weight =m1g
the second body weight =m2g
density of first body =d1
density of second body=d2
apparent weight of body=actual weight of body-force of buoyance
A.W=m1g-dvg (v=vbuoyant force)
from weight
A.W=m2g-dvg (v=volume of water)
m1g-dvg=m2g-dvg
m1-(dm1/d1)=m2-(dm2/d2)
m1(1-(d/d1))=m2(1-(d/d2))
m1=m2[1-d1/d2]/[1-d1/d2]
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