Physics, asked by n112166, 19 days ago

a body of density Rho is floating with one fourth inside the liquid A of density Rho1 and remaining in liquid B of density Rho 2. Then, find relation between Rho, Rho 1 and Rho 2​

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Answered by abhigyan007767
0

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Giventhedensityofthebody=ρandvolume=VThereforethemassofthebody=VρForafloatingbodyintwoliquids,Weightofthebody=Buoyantforceofliquid1+Buoyantforceofliquid2Weightofthebody=VρgGiven,volumeofbodyimmersedinliquidofdensityρ1=V1and,volumeofbodyimmersedinliquidofdensityρ2=V2therefore,Buoyantforceofliquid1=V1ρ1g[accordingtothelawoffloatation.Buoyantforceofliquid2=

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