Question

A body of dimensions 1.5 m ×1 m ×2m, weight 1962 N in water. Find its weight in air.What will be its epecific gravity?

Answer 1

Answer:

1.5m*1m*2m=3*1962=5886

Answer 2

Step-by-step explanation:

Given A body of dimensions 1.5 m ×1 m × 2 m, weight 1962 N in water. Find its weight in air. What will be its specific gravity?

• Weight of stone in air = weight of water displaced + weight of stone in water.
•                = 9.81 x 1000 x 1.5 x 1 x 2 + 1962
•                = 29430 + 1962
•                = 31392 KN
• So weight in air is 31392 KN
• Weight of water displaced = weight of stone in air – weight of stone in water
•                                          = 31392 – 1962
•                                           = 29430
• Volume of water displaced = volume of stone
•                                             = 29430 / 9.81 x 1000
•                                             = 3 m^3
•      Density of stone = mass / volume
•                                 = 31392 / 9.81 x 3
•                                 = 1066.66 kg /m^3
• Specific gravity = Density of stone / Density of water
•                           = 1066.66 / 997
•                           = 1.069

Reference link will be

https://brainly.in/question/40983821