Question

a body of length 1m having cross sectional area 0.75 m^2 has heat flow through it at the rate of 6000J/s the difference between two ends of conductor if K=200 J/mK isans:40°C

Answer 1

Explanation:

Heat flow per second H = K A (t2 - t1) /d

Here ,

K => 200 J/smK

A => 0.75 m^2

d = 1 m

H = 6000 J/s

Then the temperature difference ,

(t2 - t1) = (6000 × 1)/(200 × 0.75) = 6000/150 = 40°C