a body of maas m is placed on a weighing machine inside a lift. what will be the reading of weighing machine when lift is moving up with an acceleration a.
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0
Answer:
Mass of the man m=40kg
Acceleration of lift in upward direction a=2m/s
2
Let the weight shown by machine be N.
Equation of motion for the body : ma=N−mg
We get N=m(a+g)
∴ N=(40)(2+10)=480 N
Thus weight of the man recorded by machine W
′
=
g
N
∴ W
′
=
10
480
=48 kg
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Explanation:
A block of mass m is placed on a weighing machine and it is also attached to a spring balance. The whole system is placed in a lift as shown in figure. Lift is moving with constant acceleration 10m/s2 in upward direction. The reading of the weighing machine is 500N and the reading of spring balance is 300N.
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